L:( x=1 or x=2 or not ( x=1 & x=2 ))
now per cases by L;
suppose LA:x=1;
......
thus A and B;
suppose LB:x=2;
......
thus A and B;
suppose LC:not (x=1 & x=2);
......
thus A and B;
end;
L1:......;
......
L1:......;
...... by L1; ここでは直前のL1が引用される